If x = sin (2 Tan 1 2) and y = sin ( ½ Tan If x = sin (2 Tan 1 2) and y = sin ( ½ Tan 1 4/3), then prove that x>y Can you please mention some steps If x = sin (2 Tan1 2) and y = sin ( ½ Tan1 4/3), then prove that x>y Can you please mention some steps Meghana , 2 years ago Grade11 × FOLLOW QUESTION We will notify on your mail & mobile when someone answers this question · Ex 22,1 Deleted for CBSE Board 21 Exams only Ex 22, 2 Important Deleted for CBSE Board 21 Exams only Ex 22, 3 Important Deleted for CBSE Board 21 Exams only Ex 22, 4 Important Deleted for CBSE Board 21 Exams only You are here · Find the value of sin(2tan^1(2/3)) cos(tan^–1 √3) If sin^ 1 (1/5) sec^1 (2)2tan^1 (1/√3) sec^1 (5) sin^1 (1/2) 2tan^1 (√3)= kπ, then k = (a) 1 (b) 2 (c) 4 (d) 5 asked Apr 12, 18 in Mathematics by Golu (106k points) inverse trigonometric functions 1 vote 1 answer Find the value of the expression sin(2tan^1(1/3) ) cos(tan^ 1 2√2) asked Aug 29,
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Evaluate tan^(2)((1)/(2)sin^(-1)(2)/(3))-Solution Tan1 1=π/4 Tan1 2 Tan1 3= Tan1 2 Tan1 3/ 1Tan1 2 Tan1 3= Tan1 1=nππ/4=ππ/4How do you express trigonometric expressions in simplest form?
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· Show that tan(1/2 sin^1 3/4) = (4 √7/3) asked Aug 9, in Mathematics by Aryan01 (501k points) cbse;The second \int\tan^2xdx is also simple if you remember that \frac {d (\tan x)}{dx}=1\tan^{2}x Open the brackets You then have three separate integrals The first ∫ x 2 d x is simple and equal to 3 x 3 The second ∫ tan 2 x d x is also simple if you remember that d x d (t a n x) = 1 tan 2 x Deducing the series expansion of \arctan(x^2) via the series expansion of \arctan(x) at0 votes 1 answer If tan θ = 1/√7, show that cosec^2 θ sec^2 θ/cosec^2 θ sec^2 θ = 3/4 asked May 4 in Trigonometry by Amishi (222k points) trigonometry;
Answr Join / Login 12th Maths Inverse Trigonometric Functions Identities Related to Inverse Trigonometric Functions If alpha = 2 sin^1 (2/3) maths If α = 2 s i n − 1 (2 / 3 · Transcript Ex 22, 11 Find the value of tan1 "2 cos " (2"sin−1" 1/2) Solving sin1 (𝟏/𝟐) Let y = sin1 (1/2) sin y = 1/2 sin y = sin (𝝅/𝟔) Range of principal value of sin −1 is (−𝜋)/2, ( 𝜋)/2 Hence, y = 𝝅/𝟔 Rough We know that sin 30° = 1/2 θ = 30° = 30 × 𝜋/180 = 𝜋/6 Since 1/2 is positive Principal value is θ ie 𝝅/𝟔 Now solving tan1 "2How do you solve trigonometric
(a) tan(x/2)=sqrt(3) (b) sin(2x)=1/2`Sin^1 4/52tan^1 1/3=Pi/2` Department of PreUniversity Education, Karnataka PUC Karnataka Science Class 12 Textbook SolutionsClick here👆to get an answer to your question ️ If alpha = 2 sin^1 (2/3) and beta = 2 tan^1 9 then 80 cosec^2 alpha 81 cosec^2 beta is equal to LEARNING APP;
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Are solved by group of students and teacher of Class 12, which is also the largest student community of Class 12 If the answer is not available please wait for a while and aClick here👆to get an answer to your question ️ Find the value of tan^2( 12 sin^1 2 3) LEARNING APP;Find the cotangent of the inverse sine of the square root of 3 over 3
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KCET 15 The value of sin 1 ( (2 √ 2/3)) sin1 ( (1/3)) is equal to (A) (π /6) (B) (π /2) (π /4) (D) (2π /4) Check Answer and Sol8 The foci of a hyperbola coincide with the foci of the ellipse $\frac{x^{2}}{25} \frac{y^{2}}{9} = 1 $ If the eccentricity of the hyperbola is 2, then the equation of the tangent to this hyperbola passing through the point (4, 6) is · This discussion on Find the principal value of sin^1( √31/2√2)?
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Is done on EduRev Study Group by Class 12 Students The Questions and Answers of Find the principal value of sin^1( √31/2√2)?Welcome to Sarthaks eConnect A unique platform where students can · First, focus on just #sin^1(1/2)#This is another way of asking, for what angle is sine equal to #"1/2"#?Recall that #sin(pi/6)=1/2# Thus, since #sin# and #arcsin# are inverse functions, #sin^1(1/2)=pi/6# Substitute this into the original expression
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All the above anwers are wrong 15 ; · so 123=1*2*3 6=6 hence proved 14 ;Share It On Facebook Twitter Email 1 Answer 1 vote answered Oct 6, by Anika01 (571k points) selected Oct 7, by Chandan01 Best answer Given
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· Misc 3 Prove 2 sin1 3/5 = tan1 24/7 We need to convert LHS in form tan1 Converting sin1 (𝟑/𝟓) to tan1 Let x = sin1 (3/5) sin x = 3/5 Now, cos x = √(1−𝑠𝑖𝑛2 𝑥) = √(1 − (3/5)^2 ) = √(1 − 9/25) = √((25 − 9)/25) = √(16/25) = 4/5 Thus, tan x = sin𝑥/cos𝑥 tan xRefer rd pg 472 17 ; · Find value of #sin (arctan (1/2) arctan (1/3))# Ans #sqrt2/2# Explanation tan x = 1/2 > arc #x = 26^@57# tan y = 1/3 > arc #y = 18^@43# #x y = 45^@# #sin (x y) = sin 45 = sqrt2/2# Answer link Related questions How do you find all solutions trigonometric equations?
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Tan(x)^23=0 Add to both sides of the equation Take the root of both sides of the to eliminate the exponent on the left side The complete solution is the result of both the positive and negative portions of the solution Tap for more steps First, use the positive value of the to find the first solution Next, use the negative value of the to find the second solution The · Transcript Misc 31 Evaluate the definite integral ∫_0^(𝜋/2) 〖sin2𝑥 tan^(−1)(sin𝑥 ) 〗 𝑑𝑥 ∫_0^(𝜋/2) 〖sin2𝑥 tan^(−1Sin^1(1/3)sin^1(2/3)=sin(√a√b/c),then find values of b/a Dear student Please write the Question in a standard form or attach an image of the question Reg
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Exact value of trigonometric expressions sin(cos^1(1/2) sin^1(3/5))If sin(x) and cos(x) are always between 1 and 1, what is the range for tan(x)?Solution Tan1 1 Tan1 2 Tan1 3=?
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· tan^2 x = 3 tanx =±√3 , so x is in all 4 quadrants x = 60° , 1° , 240° , 300° 2 tanx sin^2 x = tanx tanx(sin^2 x 1) = 0 tanx = 0 or sinx = ± 1 if tanx = 0 , x = 0°, 180°, 360° if sinx= ±1, then x = 90°, 270° 3 cosx(2sinx 1) = 0 cosx = 0 or sinx = 1/2 if cosx = 0, then x = 90°, 270° if sinx = 1/2, then x = 30°, 150° I assume you know how to convert these to radians if · Example 4 Show that tan1 1/2 tan1 2/11 = tan1 3/4 Taking LHS tan1 1/2 tan1 2/11 = tan1 (1/2 2/11)/(1− 1/2 × 2/11) = tan1 (1/2 2/11)/(1− 1/11Solve your math problems using our free math solver with stepbystep solutions Our math solver supports basic math, prealgebra, algebra, trigonometry, calculus and more
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Get more at http//msolvedcomFind the unique solution to tansin^1(1/2)Let `sin^(1) 3/5 = x " Then " sin x = 3/5 => cos x = sqrt(1 sin^2x) = 4/5 => sec x = 5/4` ` tan x = sqrt(sec^2 x 1) = sqrt(25/16 1) = 3/4`Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with stepbystep explanations, just like a math tutor
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First Method 2tan^1(1/2)sin^1(3/5) =tan^1(1/2)tan^1(1/2)sin^1(3/5) =tan^1(1/21/2)/(1–1/2×1/2) tan^1(3/4) =tan^1(4/3) tan^1(3/4) =tan^1(4/33 · If sin1 (2a/1a2) cos1(1a2/1a2) = tan1(2x/1x2),where a, x ∈ 0,1) then the value of x is asked Mar 23, 18 in Class XII Maths by nikita74 ( · Tan^2(1/2 sin^1 2/3) 1 See answer nothingbro07 is waiting for your help Add your answer and earn points janani66 janani66 Answer tan ^ 2(1/2sin ^1 2/3 that solve answer New questions in Math The sum of three numbers is 57 The second number is 2 times the first The third number is 18 less than the second what is the third number sis you are rightbut its my habbithave
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Answer to Evaluate fully { sin(tan^{1}(1))\\ tan(sin^{1}(\frac{1}{2}) \\ sin^{1}(sin(3\pi)) \\ cos(sin^{1}(x)) \\Tan 2 (t) 1 = sec 2 (t) 1 cot 2 (t) = csc 2 (t) Advertisement Note that the three identities above all involve squaring and the number 1 You can see the PythagoreanThereom relationship clearly if you consider the unit circle, where the angle is t, the "opposite" side is sin(t) = y, the "adjacent" side is cos(t) = x, and the hypotenuse is 1 We have additional identities related to the · If x = sin(2tan1 2), y = sin(1/2tan1 (4/3)) then prove that y 2 = 1 x inverse trigonometric functions;
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Find an answer to your question Tan^2(1/2 sin^1 2/3) 1 Log in Join now 1 Log in Join now Ask your question nothingbro07 4 weeks ago Math Secondary School 5 pts Answered Tan^2(1/2 sin^1 2/3) 1 See answer AnswersFree math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with stepbystep explanations, just like a math tutorClick here👆to get an answer to your question ️ Prove 3sin^1x = sin^1 ( 3x 4x^3 ) ,x∈ 1/2 ,1/2
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1) 0 2) (√5 – 4√2)/9 3) (√5 4√2)/9 4) π/2 Answer (3) (√5 4√2)/9 Solution Given, sin1 (1/3) sin1 (2/3) = sin1 (x) Using the formula sin · Ex 22,1 Deleted for CBSE Board 21 Exams only Ex 22, 2 Important Deleted for CBSE Board 21 Exams only Ex 22, 3 Important Deleted for CBSE Board 21 Exams only · So since #x = sin^1(2/3)#, we need to find #cos(x) = cos(sin^1(2/3))# If you draw a right triangle in QI with hypotenuse 3 and opposite side 2 you can find the adjacent side is #sqrt(5)# , so #cos(x) = cos(sin^1(2/3)) = sqrt(5)/3#
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Tan(sin^1(1/2)) find the exact value · Ex 22, 18 tan (sin−1 3/5 cot−1 3/2 ) We write sin1 3/5 & cot1 3/2 in terms of tan1 Let sin−1 3/5 = a & cot−1 3/2 = b So, our equation becomes tan (sin−1 𝟑/𝟓 cot−1 𝟑/𝟐 ) = tan (a b) = 𝒕𝒂𝒏〖𝒂 𝒕𝒂𝒏𝒃 〗/(𝟏 − 𝒕𝒂𝒏〖𝒂 𝒕𝒂𝒏𝒃 〗 ) Finding tan a Since a = sin−1 𝟑/𝟓 sin aAnswr Login Join Now 12th Maths Inverse Trigonometric Functions Inverse Trigonometric Functions Find the value of tan^2( 1 maths Find the value of tan 2 (2 1 sin − 1 3 2 ) MEDIUM Answer cos 2 θ = 1 tan 2 θ 1 − tan 2 θ ⇒ cos 2 θ
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Share It On Facebook Twitter Email 1 Answer 1 vote answered Nov 10, 19 by SumanMandal (545k points) selected Nov 10, 19 by Vikash Kumar Best answer we have x = sin(2tan1 2), ← Prev Question Next Question → Related questions 0Tan(x)=12 Take the inverse tangent of both sides of the equation to extract from inside the tangent Evaluate The tangent function is positive in the first and third quadrants To find the second solution, add the reference angle from to find the solution in the fourth quadrant Simplify the expression to find the second solution Tap for more steps Remove the parentheses
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